Einzelnen Beitrag anzeigen

WojTec

Registriert seit: 17. Mai 2007
480 Beiträge
 
Delphi XE6 Professional
 
#4

Re: Show dialog when processing data

  Alt 30. Jun 2011, 13:02
Thanks guys. Depend on your advices I made this:

Delphi-Quellcode:
procedure TForm1.Button1Click(Sender: TObject);
begin
  JvThread1.Execute(Self);
end;

procedure TForm1.FormClose(Sender: TObject; var Action: TCloseAction);
begin
  if not JvThread1.Terminated then
    JvThread1.Terminate
  ;
end;

procedure TForm1.JvThread1Begin(Sender: TObject);
begin
  ProcessingDialog := TProcessingDialog.Create('Heavy Task');
  ProcessingDialog.Show;
end;

procedure TForm1.JvThread1CancelExecute(CurrentThread: TJvThread);
begin
  JvThread1Finish(Self);
end;

procedure TForm1.JvThread1Execute(Sender: TObject; Params: Pointer);
var
  I: Integer;
begin
  for I := 0 to 100000 do
  begin
    TForm1(Params).Value := I;
    JvThread1.Synchronize(TForm1(Params).UpdateStatus);

    if JvThread1.Terminated then
      Break
    ;
  end;
end;

procedure TForm1.JvThread1Finish(Sender: TObject);
begin
  ProcessingDialog.Free;
end;

procedure TForm1.UpdateStatus;
begin
  Caption := IntToStr(Value);
end;
Yes, I know, is completely lame, because uses component. But is simple

So, it working if I just open dialog, but I want to modal dialog (to lock access to interface), but when ShowModal(), thread don't execute. There is solution on this?
  Mit Zitat antworten Zitat