Hallo,
ich habe das mit dem Multicast aus der
MSDN, dort heißt es
hier:
Zitat:
Once the second socket has successfully bound, the behavior for all sockets bound to that port is indeterminate. For example, if all of the sockets on the same port provide
TCP service, any incoming
TCP connection requests over the port cannot be guaranteed to be handled by the correct socket — the behavior is non-deterministic. A malicious program can use SO_REUSEADDR to forcibly bind sockets already in use for standard network protocol services in order to deny
access to those service. No special privileges are required to use this option.
The
exception to this non-deterministic behavior is multicast sockets. If two sockets are bound to the same interface and port and are members of the same multicast group, data will be delivered to both sockets, rather than an arbitrarily chosen one.
Und über Multicasts kann man dann
hier etwas lesen. Für mich sind das aber böhmische Dörfer ...
Oder gibt es eine andere Lösung dieses Problem zu lösen?
Gruß,
Steffen