Wie wäre es, wenn du beim Umrechnen 1 addierst, dann beim Zugriff auf dein Charset aber wieder den jeweiligen Index um 1 verminderst?
Code:
0 => 0 => 0+1 = 1 => 0 => a
1 => 1 => 1+1 = 2 => 1 => b
2 => 2 => 2+1 = 3 => 2 => c
3 => 3 => 3+1 = 4 => 3 => d
4 => 4 => 4+1 = 5 => 4 => e
5 => 5 => 5+1 = 6 => 5 => f
6 => 10 => 10+1 = 11 => 00 => aa
7 => 11 => 11+1 = 12 => 01 => ab
8 => 12 => 12+1 = 13 => 02 => ac
Ist nur ein Workaround, dürfte aber das liefern, was du möchtest.
Axel Sefranek
A programmer started to cuss, cause getting to sleep was a fuss.
As he lay there in bed, looping round in his head
was: while(!asleep()) ++sheep;