Zwei Tabellen verknüfen

[Luckie]

Da muss was falsch sein:

Code:

$query = "SELECT
                     a.*,
                     k.name as k_name
                     FROM adressen a
                     LEFT OUTER JOIN adr_kategorien k on k.id a.kategorie_id";

Zitat:

Warning: mysql_fetch_object(): supplied argument is not a valid MySQL result resource