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Ergebnis der Suchanfrage


Datum des Suchindex: Heute, 13:47

Parameter dieser Suchanfrage:

Suche in Thema: Black and white - advanced
Suche alle Beiträge, die von "Medium" geschrieben wurden
• Suchmethode: "Suche nach allen Begriffen"
• Nach Datum (firstpost) sortiert
• Zeige Treffer als Beiträge
Zeige 4 von insges. 4 Treffern
Suche benötigte 0.004s

Es liegen Ergebnisse in folgenden Bereichen vor:

  • Forum: Multimedia

    AW: Black and white - advanced

      Delphi
      by Medium, 5. Dez 2010
    I've just tried that filter out, and it seems that PS goes about this entirely differently. It seems to use a combined RGBCYM-model, since settings for red do not influence magenta or yellow results at all, although red is a part of these in the pure RGB model. PS is known for compliance with a variety of differing color models (see this for some of them), and probably uses either Lab or another...
  • Forum: Multimedia

    AW: Black and white - advanced

      Delphi
      by Medium, 4. Dez 2010
    Too few infos. What type is "Luminosity" of, and how is IntToByte() implemented?

    Also, it usually is a good idea to re-order your calculation, and go with floats as long as possible to avoid nasty early rounding errors:



    var
    L: Byte;
    temp: Single;
    C, M, Y: Single;
  • Forum: Multimedia

    AW: Black and white - advanced

      Delphi
      by Medium, 4. Dez 2010
    Uhm, I wasn't aware of that PS permits values <0%. In that case you simply flow under "MinChannelValue", which is basically the same as the overflow as with too big values, just from the other side. Simply limit Luminosity to 0 (i.e.: L = max(L, 0) as a last step).
  • Forum: Multimedia

    AW: Black and white - advanced

      Delphi
      by Medium, 4. Dez 2010
    Let's start from how "simple" b&w conversions work: L = (r+g+b)/3 right? So each color component of the rgb model is added together, and then divided by the number of contributors. Written differently this gives:
    L = r/3 + g/3 + b/3, or L = i1*r + i2*g + i3*b, with in=1/3
    The in can now be changed to control how much the intensity of each channel contributes to the resulting luminance. If we...


URL zu dieser Suchanfrage:

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